What is the axis of symmetry of h(x)= 5x^2+40x+ 64? Question What is the axis of symmetry of h(x)= 5x^2+40x+ 64? in progress 0 Math Alexandra 2 months 2021-10-05T11:21:34+00:00 2021-10-05T11:21:34+00:00 2 Answers 0 views 0

## Answers ( )

Answer:Axis of symmetry is x = -4

Step-by-step explanation:h(x)= 5x^2+40x+ 64

Use the formula for axis of symmetry: x = -b/(2a)

Here, a = 5, b = 40, c = 64

so

x = -40/(2*5) = -40/10 = -4

Axis of symmetry is x = -4

Answer: x=-4

Step-by-step explanation: